2016年全国计算机等级考试四级上机编程题型

以下计算机四级考试编程题是由为大家整理的，希望能给大家的复习提供一定的帮助!

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试题说明:

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已知在文件IN.DAT中存有若干个(个数<200)四位数字的正整数,函数ReadDat()是读取这若干个正整数并存入数组xx中。请编制函数 CalValue(),其功能要求:1.求出这文件中共有多少个正整数totNum;2.求这些数中的百位数位置上的数字是1、5和7的数的个数 totCnt,以及满足此条件的这些数的算术平均值totPjz,最后调用函数WriteDat()把所求的结果输出到文件OUT7.DAT中。

注意:部分源程序存放在PROG1.C中。

请勿改动主函数main()、读数据函数ReadDat()和输出数据

函数WriteDat()的内容。

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程序:

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#include

#include

#defineMAXNUM200

intxx[MAXNUM];

inttotNum=0;

inttotCnt=0;

doubletotPjz=0.0;

intReadDat(void);

voidWriteDat(void);

voidCalValue(void)

{

}

voidmain()

{

clrscr();

if(ReadDat()){

printf("数据文件IN.DAT不能打开!�07 ");

return;

}

CalValue();

printf("文件IN.DAT中共有正整数=%d个 ",totNum);

printf("符合条件的正整数的个数=%d个 ",totCnt);

printf("平均值=%.2lf ",totPjz);

WriteDat();

}

intReadDat(void)

{

FILE*fp;

inti=0;

if((fp=fopen("in.dat","r"))==NULL)return1;

while(!feof(fp)){

fscanf(fp,"%d,",&xx[i++]);

}

fclose(fp);

return0;

}

voidWriteDat(void)

{

FILE*fp;

fp=fopen("OUT7.DAT","w");

fprintf(fp,"%d %d %.2lf ",totNum,totCnt,totPjz);

fclose(fp);

}

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所需数据:

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@2IN.DAT016

6045,6192,1885,3580,8544,6826,5493,8415,3132,5841,

6561,3173,9157,2895,2851,6082,5510,9610,5398,5273,

3438,1800,6364,6892,9591,3120,8813,2106,5505,1085,

5835,7295,6131,9405,6756,2413,6274,9262,5728,2650,

6266,5285,7703,1353,1510,2350,4325,4392,7573,8204,

7358,6365,3135,9903,3055,3219,3955,7313,6206,1631,

5869,5893,4569,1251,2542,5740,2073,9805,1189,7550,

4362,6214,5680,8753,8443,3636,4495,9643,3782,5556,

1018,9729,8588,2797,4321,4714,9658,8997,2080,5912,

9968,5558,9311,7047,6138,7618,5448,1466,7075,2166,

4025,3572,9605,1291,6027,2358,1911,2747,7068,1716,

9661,5849,3210,2554,8604,8010,7947,3685,2945,4224,

7014,9058,6259,9503,1615,1060,7787,8983,3822,2471,

5146,7066,1029,1777,7788,2941,3538,2912,3096,7421,

9175,6099,2930,4685,8465,8633,2628,7155,4307,9535,

4274,2857,6829,6226,8268,9377,9415,9059,4872,6072,

#E

@3$OUT7.DAT003

|160|47|5448.32

#E